mod int
(math/mint.hpp)

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• Last update: 2022-07-06 23:37:31+09:00
• Include: #include "math/mint.hpp"

Mint

• 自動で mod を取る整数型

Required by

• combination mod 組み合わせ (math/comb.hpp)

Verified with

• test/comb.aoj_DPL_5_E.test.cpp
• test/modint_pow.aoj_DPL_5_A.test.cpp

Code

#pragma once
#include<iostream>
using namespace std;
const int mod = 1000000007;

struct mint {
  long long x;
  mint(long long x = 0) : x((x % mod + mod) % mod) {}
  mint operator-() const { return mint(-x); }
  mint& operator+=(const mint& a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint &operator-=(const mint& a) {
    if ((x += mod - a.x) >= mod) x -= mod;
    return *this;
  }
  mint &operator*=(const mint& a) {
    (x *= a.x) %= mod;
    return *this;
  }
  mint operator+(const mint a){ return mint(*this) += a; }
  mint operator-(const mint a){ return mint(*this) -= a; }
  mint operator*(const mint a){ return mint(*this) *= a; }
  mint pow(long long t) const {
    if(!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if(t&1) a *= *this;
    return a;
  }
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint& a) { return *this *= a.inv(); }
  mint operator/(const mint& a){ return mint(*this) /= a; }
};
mint pow(mint a, long long b){
    return a.pow(b);
}
istream& operator>>(istream& is, mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }

#line 2 "math/mint.hpp"
#include<iostream>
using namespace std;
const int mod = 1000000007;

struct mint {
  long long x;
  mint(long long x = 0) : x((x % mod + mod) % mod) {}
  mint operator-() const { return mint(-x); }
  mint& operator+=(const mint& a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint &operator-=(const mint& a) {
    if ((x += mod - a.x) >= mod) x -= mod;
    return *this;
  }
  mint &operator*=(const mint& a) {
    (x *= a.x) %= mod;
    return *this;
  }
  mint operator+(const mint a){ return mint(*this) += a; }
  mint operator-(const mint a){ return mint(*this) -= a; }
  mint operator*(const mint a){ return mint(*this) *= a; }
  mint pow(long long t) const {
    if(!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if(t&1) a *= *this;
    return a;
  }
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint& a) { return *this *= a.inv(); }
  mint operator/(const mint& a){ return mint(*this) /= a; }
};
mint pow(mint a, long long b){
    return a.pow(b);
}
istream& operator>>(istream& is, mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }

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